1.

find the greatest number of 4 digit when divided by 7 10 15 21 and 28 leaves the remainders 5 8 13 19 26 respectively​

Answer»

Answer:

9658

Step-by-step explanation:

You can see the difference between divisor and remainder is 2

7-5=10-8=15-13=21-19=28-26===========2

LARGEST 4 digit number=9999

LCM of 7,10,15,21,28=420

9999=420×23+339

9999-339=9660

Means 9660 is largest 4 digit no that is completely divisible by GIVEN numbers .

But after subtracting 2 we get the REQUIRED n.

9660-2=9658

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