Find the following products:\((-\frac{7}{4}ab^2c-\frac{6}{25}a^2c^2)(-

1.	Find the following products:\((-\frac{7}{4}ab^2c-\frac{6}{25}a^2c^2)(-50a^2b^2c^2)\)
Answer» (\(\frac{-7}{4}\)ab²c - \(\frac{6}{25}\)a²c²) (-50a²b²c²) = \(\frac{-7}{4}\)ab²c × -50a²b²c² - \(\frac{6}{25}\)a²c² × -50a²b² × c² = \(\frac{7}{4}\) × 50 × a³ × b⁴ × c³ - \(\frac{6}{25}\) × - 50 × a⁴ × b² × c⁴ = \(\frac{350}{4}\)a³b⁴c³ + 12a⁴b²c⁴ = \(\frac{175}{2}\)a³b⁴c³ + 12a⁴b²c⁴ here the product is given as [\((-7/4) \) ab²c - \(6/25\) a²c² ] (-50a²b²c²) = \(225/2\) a³b⁴c³ + 12 a⁴b²c⁴

Find the following products:\((-\frac{7}{4}ab^2c-\frac{6}{25}a^2c^2)(-50a^2b^2c^2)\)

Answer»

(\(\frac{-7}{4}\)ab²c - \(\frac{6}{25}\)a²c²) (-50a²b²c²)

= \(\frac{-7}{4}\)ab²c × -50a²b²c² - \(\frac{6}{25}\)a²c² × -50a²b² × c²

= \(\frac{7}{4}\) × 50 × a³ × b⁴ × c³ - \(\frac{6}{25}\) × - 50 × a⁴ × b² × c⁴

= \(\frac{350}{4}\)a³b⁴c³ + 12a⁴b²c⁴

= \(\frac{175}{2}\)a³b⁴c³ + 12a⁴b²c⁴

here the product is given as

[\((-7/4) \) ab²c - \(6/25\) a²c² ] (-50a²b²c²)

= \(225/2\) a³b⁴c³ + 12 a⁴b²c⁴