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find the focal length and nature of lens which should be placed in contact with a concave lens of focal length 25 cm from a real image five times the size of the object placed 20cm from the combination |
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Answer» f1 = 25 cm = 0.25 mp1 = 1/f1 = 1/0.25 = 4Df2 = -10 cm = -0.1mp2 = 1/f2 = 1/-0.1 = -10D(a) Power of the combination:P = p1 + P2= 4D + (-10D)= - 6 D(B) FOCAL length of the combination:f = 1/P = 1/-6 = -0.1666m = -16.66cm(c) The combination has NEGATIVE focal length, so it is diverging. |
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