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Find the first terms of an A.P., whose 3rd term is 3 and 8th term is 33. |
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Answer» Answer: a3 = 3 a8 = 33 a + 7d = 33 a+ 2d = 3 ---------------- 5d = 30 d= 30/5 d= 6 substitute d=6 in equation 1 a+2d= 3 a+ 2(6)= 3 a+12= 3 a= 3-12 a= -9 |
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