1.

Find the equivalent resistance of the following figures.Give your answer with detailed explanation. (necessary steps)​

Answer»

Answer:

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<U>a) Figure 'a ' is type of parallel connection

Formula =

\frac{1}{r1 } + \frac{1}{<klux>R2</klux>} \\ = \frac{1}{2} + \frac{1}{2} = \frac{2}{2} ohm = 1ohm

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c) Figure 'c' is also parallel connection

Formula =

\frac{1}{r1 } + \frac{1}{r2} \\ = \frac{1}{1} + \frac{1}{1} = \frac{2}{1} \\ = \frac{1}{2} ohm \\ \: \: \: \: \:

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b) Figure 'b' is also parallel connection

Formula =

By applying parallel's formula

We'll get the answer 1/R = 5/2

==> R = 2/5 ohm

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d) Figure ' d' is both parallel & SERIES connection

Using parallel's formula

Formula = 1/R1 +1/R2 =1/1 +1/1 = 2/1

==> R = 1/2 ****

1/R1 + 1 R2 = 1/1+ 1/1 = 2/1

==> R=1/2***

Applying series's formula

=R1+R2= 1/2+1/2 = 2/2ohm

= 1 ohm

^❤^ HOPE this'll help U Loveen


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