Find the equation of the the circle with centre at ( -3,-2 ) and r = 6

1.	Find the equation of the the circle with centre at ( -3,-2 ) and r = 6
Answer» $\large{\underline{\underline{\mathfrak{\green{\sf{QUESTION:-}}}}}}$ . FIND the equation of the the circle with CENTRE at ( -3,-2 ) and r = 6...? $\large{\underline{\underline{\mathfrak{\red{\sf{SOLUTION:-}}}}}}$ . $\large{\underline{\underline{\mathfrak{\bf{Given\:Here:-}}}}}$ . Centre of circle (-3,-2,) and , RADIUS r = 6. $\large{\underline{\underline{\mathfrak{\sf{Find\:Here:-}}}}}$ . Equation of Circle $\large{\underline{\underline{\mathfrak{\sf{Explanation:-}}}}}$ . we know that , Equation of circle with centre (h,k) and radius r $\large{\boxed{\boxed{\:(x-h)^2\:+\:(y-k)^2\:=\:r^2}}}$ Where, h = -3, k = -2 and, r = 6 , $\implies\:\left\{x-(-3)\right\}^2\:+\:\left\{y-(-2)\right\}^2\:=\:(6)^2$ $\implies\:(x+3)^2\:+\:(y+2)^2\:=\:36$ $\implies\:(x^2+y^2+6x+4y+13)\:=\:36$ $\large{\boxed{\boxed{\:(x^2+y^2+6x+4y-23)\:=\:0}}}$ ___________________

Answer»

$\large{\underline{\underline{\mathfrak{\green{\sf{QUESTION:-}}}}}}$ .