Saved Bookmarks
| 1. |
Find the equation of the tangent to the parabola `y^2=8x`having slope 2 and also find the point of contact. |
|
Answer» The equation of the tnagent to `y^(2)=4ax` having slope m is `y=mx+(a)/(m)` Hence, for the given parabola, the equation of the tangent is `y=2x+(2)/(2)ory=2x+1` and the point of contact is `((a)/(m^(2)),(2a)/(m))-=((2)/(2^(2)),(2(2))/(2))-=((1)/(2),2)` |
|