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find the equation of the set of the points which are equal distance from the points a(1,-2,5) & b(0,4,-1) |
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Answer» ONG>Answer: 2x-12y+12z-13=0 Step-by-step explanation: which is equidistant from POINTS A and B so PA=PB square on both sides PA²=PB² now distance = √[(x2-x1)² +(y2-y1)² +(z2-z1)²] so using this PA² = PB² that GIVES (x-1)²+(y+2)²+(z-5)² = (x-0)²+(y-4)²+(z+1)² x²+1-2x+y²+4+4y+z²+25-10z = x²+y²+16-8y+z²+1+2z on simplifying -2x+12y-12z+13=0 2x-12y+12z-13=0 |
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