1.

Find the equation of the set of points which are equidistant from the points (1, 2, 3) and (3,2,-1). 

Answer»

Let A (1, 2, 3) and B (3, 2, -1) be the given points. 

Let P(x, y, z) be any point equidistant from A and B, then

PA = PB (i.e., PA2 = PB2)

⇒ ((x - 1)2 + (y - 2)2 + (z - 3)2)

((x - 3)2 + (y - 2)2 + (z + 1)2)

⇒ x2 - 2x + 1+ y2 – 4y + 4 + z2  + 2z + 1 

⇒ x2- 6x + 9 + y2- 4y + 4 + z2  + 2z + 1 

⇒ 4x – 8z = 0 

⇒ x – 2z = 0 is the required equation.



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