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Find the equation of the set of points which are equidistant from the points (1, 2, 3) and (3,2,-1). |
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Answer» Let A (1, 2, 3) and B (3, 2, -1) be the given points. Let P(x, y, z) be any point equidistant from A and B, then PA = PB (i.e., PA2 = PB2) ⇒ √((x - 1)2 + (y - 2)2 + (z - 3)2) = √((x - 3)2 + (y - 2)2 + (z + 1)2) ⇒ x2 - 2x + 1+ y2 – 4y + 4 + z2 + 2z + 1 ⇒ x2- 6x + 9 + y2- 4y + 4 + z2 + 2z + 1 ⇒ 4x – 8z = 0 ⇒ x – 2z = 0 is the required equation. |
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