Saved Bookmarks
| 1. |
Find the equation of the plane through (4,5, -6) and parallel to the plane 2x + 3y + 5z + 6 = 0 |
|
Answer» Let the required plane be P: Ax + By +Cz + D = 0 Given P//P1: 2x + 3y + 5z + 6 = 0, hence their normals will also be parallel, & will have the same direction ratios. Hence, P: 2x + 3y + 5z + D = 0 Since the point (4, 5, -6) lies on P, it will satisfy it's equation. Replacing the values: 2(4) + 3(5) +5(-6) + D = 0 D = 30 -15 - 8 = 7 Equation of P: 2x + 3y + 5z + 7 = 0 Hence found. |
|