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Find the equation of the parabola which has axis parallel to the y-axisand which passes through the points `(0,2),(-1,0),a n d(1,6)dot` |
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Answer» General equation of parabola having axis parallel to y-axis is `y=Ax^(2)+Bx+C` It passes through the points (0,2), (-1,0) and (1,6). Then we have, C=2 (1) A-B+C=0 (2) A+B+C=6 (3) Solving (1), (2) and (3), we get C=2, A=1 and B=3. Therefore, equation of parabola is `y=x^(2)+3x+2`. |
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