Find the equation of the circle with radius 5 whose center lies on thex-axis and passes through the point (2, 3).

Find the equation of the circle with radius 5 whose center lies on the

1.	Find the equation of the circle with radius 5 whose center lies on thex-axis and passes through the point (2, 3).
Answer» Since the radius of the circle is 5 and its center lies on the x-axis, the equation of the circle is `(x-h)^(2)+y^(2)=25`. It is given that the circle passes through the point (2,3). Therefore, `(2-h)^(2)+3^(2)=25` or `(2-h^(2))=16` or `2-h=+-4` If `2-h=4,` then `h=2` If `2-h= -4` then `h=6` Therefore , the equation of circle is `(x+2)^(2)+y^(2)=25` or `(x+6)^(2)+y^(2)=25`. Hence, `x^(2)+y^(2)+4x-21=0` or `x^(2)+y^(2)-12x+11=0`

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Find the equation of the circle with radius 5 whose center lies on thex-axis and passes through the point (2, 3).

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