Find the equation of the circle whose centre is in the first quadrant

1.	Find the equation of the circle whose centre is in the first quadrant and radius 4
Answer» We KNOW that the equation of a circle with center (H,k) and radius r units is (x−h)²+(y−k)²=r² . or, acc to the question, centre is in the first quadrant and radius 4. That MEANS h = k = 4 units. i.e. (4,4) SINCE it's the first quadrant the centre will be (h,k) Therefore, equation will be: (x−4)²+(y−4)²=4² or, (x−4)²+(y−4)² = 16 [ANS]

Find the equation of the circle whose centre is in the first quadrant and radius 4

Answer»

We KNOW that the equation of a circle with center (H,k) and radius r units is (x−h)²+(y−k)²=r² .

or, acc to the question, centre is in the first quadrant and radius 4. That MEANS h = k = 4 units. i.e. (4,4) SINCE it's the first quadrant the centre will be (h,k)

Therefore, equation will be:

(x−4)²+(y−4)²=4²

or, (x−4)²+(y−4)² = 16 [ANS]

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Find the equation of the circle whose centre is in the first quadrant and radius 4

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