Find the equation of the circle which passesthrough the point of inter

1.	Find the equation of the circle which passesthrough the point of intersection of the lines3x-2y-1 = 0 and 4x+ y - 27=0 and whose centre is (2,-3).
Answer» The POINT of intersection is the SOLUTION of system of equation $\left \{ {{3x-2y-1=0} \atop {4x+y-27=0}} \right.$ . The point of intersection is $(5,7)$ . The CENTRE of the circle is $(2,-3)$ . Let the RADIUS of the circle be $r$ . Then $r^2=3^2+10^2=109$ . the equation ∴ $(x-2)^2+(y+3)=109$ (+ Attatchment)