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find the equation of the circle which passes through the origin and cuts off intercepts of 'a' , each from positive directions of the axes. |
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Answer» Step-by-step explanation: x^2 + y^2 + 2gx +2fy+c= 0 solve this for the THREE points and you will get your required EQUATION of the circle. METHOD 2: You can USE another method. Just see thecircle goes through the origin and at the origin x and y axis are perpendicular and you also know that semicircular ANGLE is a right angle. |
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