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Find the equation of the circle, which passes through theorigin and makes intercepts 3 and 4 on the axes.3. |
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Answer» Since, the circle cuts intercepts of a and b on the x – axis and y – axis respectively, therefore, the line joining the points (a, 0) and (0, b) will be the diameter of the circle. Let the co-ordinates of the centre of the circle behandkrespectively. Therefore,h= (a+ 0)/2 andk= (b+ 0)/2 Let the radius of the circle ber Therefore,r^2= (0.5a–a)^2 + (0.5b– 0)^2 Equation of the circle is as follows: (x–h)^2+ (y–k)^2=r^2 Equation:x^2+y^2–ax–by= 0hence here a=3 and b=4x^2+y^2-3x-4y=0 |
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