Find the equation of the circle, the coordinates of the end points of

1.	Find the equation of the circle, the coordinates of the end points of one of whose diameters are
Answer» The equation of a circle passing through the coordinates of the end points of diameters is: (x - x₁) (x - x₂) + (y - y₁)(y - y₂) = 0 Substituting, values:(x₁, y₁) = (3, 2) & (x₂, y₂) = (2, 5) We get: (x - 3)(x - 2) + (y - 2)(y - 5) = 0 ⇒ x² - 2x - 3x + 6 + y² - 5y - 2y + 10 = 0 ⇒ x² + y² - 5x - 7y + 16 = 0 x² + y² - 5x - 7y + 16 = 0

Find the equation of the circle, the coordinates of the end points of one of whose diameters are

Answer»

The equation of a circle passing through the coordinates of the end points of diameters is:

(x - x₁) (x - x₂) + (y - y₁)(y - y₂) = 0

Substituting, values:(x₁, y₁) = (3, 2) & (x₂, y₂) = (2, 5)

We get:

(x - 3)(x - 2) + (y - 2)(y - 5) = 0

⇒ x² - 2x - 3x + 6 + y² - 5y - 2y + 10 = 0

⇒ x² + y² - 5x - 7y + 16 = 0

x² + y² - 5x - 7y + 16 = 0

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Find the equation of the circle, the coordinates of the end points of one of whose diameters are

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