1.

Find the equation of the circle passing through the Points (4, 1)and (6, 5) and whose centre is on the line is 4x + y = 16​

Answer»

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Given POINTS,

(4,1),(6,5)

EQUATION of circle (x-h)2+(y-k)2=r2

- (4-h)2+(1-k)2=r2 (1)

→ (6-h)2+(5-k)2=r2 (2)

solving the above 2 EQUATIONS, we get,

h+2k=11 (3)

given, 4h+k=16 (4)

solving the above 2 equations, we get,

h=3,K=4

substituting the above values in (1), we get,

(4-3)2+(1-4)2=r2

r=10

Hence, the equation is,

46 14 1 97%

142

8

x 5.0

(x-3)2+(y-4)2=(10)2

X2+y2-6x-8y+15=0



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