1.

Find the equation of the chord of the parabola `y^(2)=8x` having slope 2 if midpoint of the chord lies on the line x=4.

Answer» Let `M(4,y_(1))` be midpoint of the chord. So, equation of chord using equation `T=S_(1)` is
`yy_(1)-4(x+4)=y_(1)^(2)-8xx4`
`or" "yy_(1)-4x=y_(1)^(2)-16`
Slope `=(4)/(y_(1))=2` (Given)
`:." "y_(1)=2`
So, equation of the chord is
2y-4x=-12
y=2x-6


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