1.

Find the equation of parabola whose vertex at the origin, the axis along the x-axis, and passesthrough (-3, 6).

Answer»

Final answer:

\\\tt y= \dfrac{2x}{3}

STEPS:

For a parabola,

\\\tt y = 4ax^2

where a is the focus,

USING coordinates (-3,6).

\\\tt 6 = (4)*a*(9)\\\\a= \dfrac{1}{6}

Therefore the EQUATION of  the parabola will be,

\\\tt y = 4(\dfrac{1}{6})x \\y= \dfrac{2x}{3}


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