. Find the equation of normals to the curve:y = 2 sin-3x at x(ii)y = ( – InterviewSolution

1.	. Find the equation of normals to the curve:y = 2 sin-3x at x(ii)y = (sin 2x + cotx + 2)2 at x=(i)=-62.
Answer» i)by differentiating we will get slope of tangentslope of normal=1/slope of tangent=1/0at x=(pi)/6 , y=2y=mx+cy=(1/0)x+cx=0 is the normal to the given curveii)same as 1

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