1.

Find the equation of line containing the points (1,2)(1,-2)​

Answer»

Given ,

The equation of line passing through the POINTS (1,2) and (1,-2)

We know that , the two point FORM is given by

\boxed{ \sf{y - y_{1} = \frac{ y_{2} - y_{1} }{x_{2} - x_{1} } (x - x_{1})}}

Thus ,

y - 2 = (-2 - 2)/(1 - 1) × (x - 1)

y - 2 = -4/0 × (x - 1)

y - 2 = 1/0 × (x - 1)

0 = x - 1

x = 1

★ The equation of the line is x = 1


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