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Find the equation of circle passing through points (5,3) (1,5) (3,-1) |
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Answer» Let the required equation of the circle is x2 + y2 + 2gx + 2fg + c = 0 But this eqn passes through the points (5,3) 10g + 6f + C + 34 = 0 (1,5) 2g + 10 f + C + 26 = 0 (3,-1) 6g – 2f + C + 10 = 0 Solving 2,3 and 4 we get 2 – 3 ⇒ 2g – f + 2 = 0 3 – 4 ⇒ g – 3f – 4 = 0 Again solving we get y = -2, f = -2, c = -2 This the required egn of the circle is x2+ y2 – 4x – 4y -2 = 0 |
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