1.

Find the equation of circle passing through points (5,3) (1,5) (3,-1)

Answer»

Let the required equation of the circle is 

x2 + y2 + 2gx + 2fg + c = 0 

But this eqn passes through the points 

(5,3) 10g + 6f + C + 34 = 0 

(1,5) 2g + 10 f + C + 26 = 0 

(3,-1) 6g – 2f + C + 10 = 0 

Solving 2,3 and 4 we get 

2 – 3 ⇒ 2g – f + 2 = 0 

3 – 4 ⇒ g – 3f – 4 = 0 

Again solving we get y = -2, f = -2, c = -2 

This the required egn of the circle is x2+ y2 – 4x – 4y -2 = 0



Discussion

No Comment Found

Related InterviewSolutions