1.

Find the equation of a straight line which has slope minus 5 by 4 and passing through the point (-1,2).

Answer»

Given :

  • Slope ( m ) = - 5/4

To Find :

  • Equation of the straight line

SOLUTION :

Point slope of line is

\large \implies \boxed{ \boxed{ \sf y - y_1 = m(x - x_1)}}

Substitute values in formula

\implies \sf y - 2 = - \frac{5}{4}(x - ( - 1)) \\ \\\implies \sf y - 2 = - \frac{5}{4}(x + 1) \\ \\ \implies \sf y - 2 = \frac{ - 5x}{4} - \frac{5}{4} \\ \\ \implies \sf y = \frac{ - 5x}{4} - \frac{5}{4} + 2 \\ \\ \implies \sf y = \frac{ - 5x}{4} - \frac{5 + 8}{4} \\ \\ \implies \sf y = \frac{ - 5x}{4} - \frac{13}{4} \\ \\ \implies \sf \frac{ 5x}{4} + y +\frac{13}{4} = 0\\ \\ \sf\implies \frac{ 5x + 4y + 13}{4} = 0 \\ \\ \large \implies \boxed{ \boxed{\sf 5x + 4y +13= 0 }}


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