1.

Find the equation of a parabola whose focus is (-3,0) and directrix is x+5=0

Answer»

According to definition of parabola , is is the locks of the points in that planes that are equidistant from both FOCUS and directrix.

Given, focus : (-3,0)
directrix : x + 5 = 0
Let (x ,y) is the point on the parabola .
∴ DISTANCE of point from focus = distance of point from directrix
⇒ √{(x + 3)² + y²} = |x + 5|/√(1² + 0²)
⇒ √{(x + 3)² + y² } = |x + 5|
squaring both sides,
(x + 3)² + y² = (x + 5)²
⇒y² = (x + 5)² - (x + 3)²
⇒y² = (x + 5 - x - 3)(x + 5 + x + 3)
⇒y² = 2(2X + 8) = 4(x + 4)

Hence, EQUATION of parabola is y² = 4(x + 4)


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