1.

Find the equation of a curve passing through (1,1) and whose slope of tangent at a point (x, y) is `-(x)/(y)`.

Answer» `because` The slope of the tangent to the curve at a point (x, y) is `(dy)/(dx)`
`(dy)/(dx) = -(x)/(y)`
`rArr xdx + ydy = 0`
Integrating both sides we get `(x^(2))/(2)+(y^(2))/(2) = c`
`because` The curve passes through (1,1)
`:. (1)/(2) + (1)/(2) = c`
`rArr c = 1`
`:.` The equation of the curve is `x^(2) + y^(2) = 2`


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