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Find the equation of a curve passing through (1,1) and whose slope of tangent at a point (x, y) is `-(x)/(y)`. |
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Answer» `because` The slope of the tangent to the curve at a point (x, y) is `(dy)/(dx)` `(dy)/(dx) = -(x)/(y)` `rArr xdx + ydy = 0` Integrating both sides we get `(x^(2))/(2)+(y^(2))/(2) = c` `because` The curve passes through (1,1) `:. (1)/(2) + (1)/(2) = c` `rArr c = 1` `:.` The equation of the curve is `x^(2) + y^(2) = 2` |
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