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Find the equation of a circle with: Centre at (2, -3) and radius 5 |
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Answer» The equation of a circle with centre at (h, k) and radius ‘r’ is given by (x – h)2 + (y – k)2 = r 2 Here, h = 2, k = -3 and r = 5 The required equation of the circle is (x – 2)2 + [y – (-3)]2 = 52 ⇒ (x – 2)2 + (y + 3)2 = 25 ⇒ x2 – 4x + 4 + y2 + 6y + 9 – 25 = 0 ⇒ x2 + y2 – 4x + 6y – 12 = 0 |
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