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Find the equation of a circle, the end points of one of whose diameters are ` A (2, -3) and B(-3, 5)`. |
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Answer» We know that the equation of a circle, the end points of one of whose diameters are `(x_1, y_1) and (x_2, y_2) `, is given by ` " "(x - x_1) (x - x _2 ) + (y -y_1 ) (y - y_2) = 0 ` Here, ` x_1 = 2, y_1 = - 3 and x_2 = - 3, y_2 = 5` ` therefore ` the required equation of the circle is ` (x - 2 ) (x + 3) + ( y + 3 ) ( y - 5)=0` ` rArr x ^(2) + y ^(2) + x - 2y - 21 = 0` |
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