Find the equation equation of straight line joining point (3, 2) and m

1.	Find the equation equation of straight line joining point (3, 2) and making positive equal intercepts on axes.
Answer» Answer: 0 Step-by-step EXPLANATION: Equation of LINE is INTERCEPT from is xa yt =1 It PASSES through (−3,8) a−3 + y8 =1 a+b=7 b=7−a a−3+ 7−a8=1 a 2+7a−21=0 (a−3)(a+7)=0 a=−3,7 For positive intercept =a=3 ⇒b=4 So the equation of line is 3x + 4y =1 4x+3y−12=0

Find the equation equation of straight line joining point (3, 2) and making positive equal intercepts on axes.

Answer»

Answer:

Step-by-step EXPLANATION:

Equation of LINE is INTERCEPT from is

It PASSES through (−3,8)

a−3 + y8

a+b=7

b=7−a

a−3+ 7−a8=1

a 2+7a−21=0

(a−3)(a+7)=0

a=−3,7

For positive intercept =a=3

⇒b=4

So the equation of line is

3x + 4y

4x+3y−12=0

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Find the equation equation of straight line joining point (3, 2) and making positive equal intercepts on axes.​

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Find the equation equation of straight line joining point (3, 2) and making positive equal intercepts on axes.