1.

Find the energy of a photon with 4000A° wavelength in water​

Answer»

E=hr(r=frequency)    =H X c/λ    =6.626 x 10^-34 x 3 x 10^8 x 4000 x 10^-10  =19.878 x 10^-34/40   =0.49655 x 10^-34 MPLEASE MARK me brainliest



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