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Find the elastic deformation energy of a steel rod of mass `m=3.1kg` stretched to a tensile strain `epsilon=1.0*10^-3`. |
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Answer» We assume that the deformation is wholly due to external load, neglecting the effect of the weight of the rod. Then a well known formula says, elastic energy per unit volume `=1/2stressxxstrai n=1/2sigmaepsilon` This gives `1/2m/rhoEepsilon^2~~0*04kJ` for the total deformation energy. |
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