1.

Find the domain and range of y =under root of 4- x square ​

Answer»

Explanation:

4−x2  ≥  0  ⇒  (2−x)  ⋅  (2+x)  ≥  0  which HOLDS for  [−2,2]  hence

D(f)  =  [−2,2]  

The RANGE is   y=√4−x2  ⇒

⇒  y  2  =4  −  x2  ⇒  x2  =  4  −  Y2  ≥  0  ⇒  (2−y)(2+y)  ≥  0

 Because  

y  ≥  0  we have that  

R(f)  =  (0,2) : Answer

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