1.

Find the domain and range of the following real functionsf(x)=\(\frac{x^2-9}{x-3}\)

Answer»

Given, f(x) =\(\frac{x^2-9}{x-3}\) 

Domain: Clearly, f(x) is defined for all x ∈ R expect x = 3 

∴ Domain of f = R – {3} = (−∞, 3),∪ (3, ∞) 

Range: Let y = f(x) 

∴ y = \(\frac{x^2-9}{x-3}\)⇒ = + 3 

It follow from the above relation that y takes all real values except 6 when takes values in the set 

R – {3} 

∴ Range of f = R – {6}



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