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Find the domain and range of the following real functionsf(x)=\(\frac{x^2-9}{x-3}\) |
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Answer» Given, f(x) =\(\frac{x^2-9}{x-3}\) Domain: Clearly, f(x) is defined for all x ∈ R expect x = 3 ∴ Domain of f = R – {3} = (−∞, 3),∪ (3, ∞) Range: Let y = f(x) ∴ y = \(\frac{x^2-9}{x-3}\)⇒ = + 3 It follow from the above relation that y takes all real values except 6 when takes values in the set R – {3} ∴ Range of f = R – {6} |
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