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Find the domain and range of `f(x)=sqrt(3-2x-x^2)` |
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Answer» Correct Answer - Domain: [-3, 1], Range: [0, 2] `f(x)=sqrt(3-2x-x^(2))` is defined if `3-2x-x^(2) ge 0` or `x^(2)+2x-3 le 0` or `(x-1)(x+3) le 0` or ` x in [-3,1]` Also, `f(x)=sqrt(4-(x+1)^(2))` which has maximum value when `x+1=0.` Hence, the range is `[0,2].` |
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