Saved Bookmarks
| 1. |
Find the distance of the point (2, 3) from the line 2x-3y + 9 = 0 measured along a linemaking an angle of 45° with the x-axis. |
|
Answer» Slope of 2x - 3y + 9 = 0 is 2/3Slope of x - y + 1 = 0 is 1Angle between the two lines= arctan (1 -2/3) / (1 + 2/3)= arctan (1/4)= 14°Perpendicular distance from (2, 3) to the line 2x - 3y + 9 = 0 isp = l 2*2 - 3*3 + 9 l / √(2^2 + 3^2) = 4 / √(13)distance of (2,3) from 2x - 3y + 9 = 0 along x - y + 1 = 0 isp sin 14°= [4/√(13)] sin14°= 0.268. |
|