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find the distance of the image, when as object is placed on the principal axis at a distance of 10 cm in front of a concave mirror whose radius of curvature is -8 cm |
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Answer» HEY mate here is ur ans u = distance of object= - 10 cm R = RADIUS of curvature = -8 so we know that f= R/2 f= -8/2 = -4 v= distance of image we know the formula 1/f= 1/v- 1/u 1/-4= 1/v- 1/-10 1/v= -1/10-1/4 1/v= -2-5/20 1/v= -7/20 v= -20/7 v = - 2.8 hope it help u |
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