Saved Bookmarks
| 1. |
)Find the distance from 4q where a third charge can remain in equilibrium.pls ans |
|
Answer» Hy dude UR ANSWER isExplanation:Let"r" be the distance from the charge Q where Q is in equilibrium .Total Force acting on Charge q and 4Q:F=kqQ/r² + k4qQ/(l-r)²For Q to be in equilibrium , F should be equated to zero.kqQ/r² + k4qQ/(l-r)²=0(l-r)²=4r²⇒l-r=2r⇒l=3r⇒r=l/3Taking the third charge to be -Q (say) and then on APPLYING the condition of equilibrium on + q chargekQ/(L/3)² =k(4q)/L²9kQ/L²=4kq/L²9Q=4qQ=4q/9Therefore a point charge -4q/9 should be placed at a distance of L/3 rightwards from the point charge +q on the line joining the 2 charges.✔Hơ℘ɛ ıɬ ɧɛƖ℘ʂ!!✔✌Mąཞƙ ɱɛ ąʂ ცཞąıŋƖıɛʂɬ☞Hıɬ ąŋɖ Ɩıƙɛ ɱყ ąŋʂῳɛཞ ąŋɖ ɖơŋ'ɬ ʄơཞɠɛɬ ɬơ ʄơƖƖơῳ ɱɛ☜ |
|