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Find the distance between the points P(-4, 7) and Q(2, -5). |
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Answer» The given points are P(-4, 7) and Q(2, -5). Then, `x_(1) = -4, y_(1) = 7 "and"x_(2) = 2, y_(2) = -5` `therefore PQ = sqrt((x_(2) -x_(1))^(2) + (y_(2) - y_(1))^(2))` `= sqrt({2-(-4)}^(2) + (-5-7)^(2)) = sqrt(6^(2) + (-12)^(2))` `=sqrt(36+144) = sqrt(180) = sqrt(36 xx 5) = 6sqrt(5)` units. |
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