1.

Find the distance between the parallel lines 3x – 4y + 7 = 0 and 3x – 4y + 5 = 0.

Answer»

d = |(c1 - c2)/(a2 + b2)|

c1 = 7 a = 3

c2 = 5 b = - 4

d = |((7) - (5))/(32 + 42)| = |2/5| = 2/5



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