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Find the distance between the parallel lines 3x – 4y + 7 = 0 and 3x – 4y + 5 = 0. |
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Answer» d = |(c1 - c2)/√(a2 + b2)| c1 = 7 a = 3 c2 = 5 b = - 4 d = |((7) - (5))/√(32 + 42)| = |2/5| = 2/5 |
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