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Find the dimensions of a rectangle with a perimeter of 54m, if itslength is 3m less than twice its width. |
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Answer» Perimeter of a RECTANGLE= 54m Width= x Length= 2x-3 Perimeter of a rectangle=2(l+b) 2(2x-3+x)=54m 2(3x-3)=54m 6x-6=54m 6x=54+6=60m x=60÷6 x=10 Width=10m Length=17m Hope it helps✌️ Please MARK it as brainliest and follow me |
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