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Find the difference between compound interest and simple interest on rs 15000 in 2yrs at 6%p.a |
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Answer» Answer: Solution :- ❶ Compound Interest Given :- P = Rs 15000 r% = 5 % n = 2 years According to the question by using the formula we get, ⇒ Amount = 15000 (1 + \dfrac{5}{100} 100 5
)² ⇒ Amount = 15000 (1+ \sf\dfrac{\cancel{5}}{\cancel{100}} 100
5
)² ⇒ Amount = 15000 (1 + \dfrac{1}{20} 20 1
)² ⇒ Amount = 15000 ( \dfrac{21}{20} 20 21
)² ⇒ Amount = 15000 × \dfrac{21}{20} 20 21
× \dfrac{21}{20} 20 21
⇒ Amount = \dfrac{66150}{4} 4 66150
➠ Amount = 16537.5 Now, we have to find the compound interest, ✦ Compound Interest = Amount - Principal ✦ ↦ Compound Interest = 16537.5 - 15000 ➟ Compound Interest = Rs 1537.5 \begin{gathered}\\\end{gathered}
❷ Simply Interest Given : P = Rs 15000 r% = 5 % t =. 2 years According to the question by using the formula we get, ⇒ S.I = \dfrac{15000 \times 5 \times 2}{100} 100 15000×5×2
⇒ S.I = \dfrac{150000}{100} 100 150000
⇒ S.I = \sf\dfrac{\cancel{150000}}{\cancel{100}} 100
150000
➠ S.I = Rs 1500 ❸ Now, we have to find the difference between C.I and S.I we get, ⇒ Difference = 1537.5 - 1500 ➥ Difference = Rs 37.5 \therefore∴ The difference between Compound Interest and SIMPLE Interest is Rs 37.5 . |
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