1.

Find the difference between compound interest and simple interest on rs 15000 in 2yrs at 6%p.a​

Answer»

Answer:

Solution :-

❶ Compound Interest

Given :-

P = Rs 15000

r% = 5 %

n = 2 years

According to the question by using the formula we get,

⇒ Amount = 15000 (1 + \dfrac{5}{100}

100

5

)²

⇒ Amount = 15000 (1+ \sf\dfrac{\cancel{5}}{\cancel{100}}

100

5

)²

⇒ Amount = 15000 (1 + \dfrac{1}{20}

20

1

)²

⇒ Amount = 15000 ( \dfrac{21}{20}

20

21

)²

⇒ Amount = 15000 × \dfrac{21}{20}

20

21

× \dfrac{21}{20}

20

21

⇒ Amount = \dfrac{66150}{4}

4

66150

➠ Amount = 16537.5

Now, we have to find the compound interest,

✦ Compound Interest = Amount - Principal ✦

↦ Compound Interest = 16537.5 - 15000

➟ Compound Interest = Rs 1537.5

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❷ Simply Interest

Given :

P = Rs 15000

r% = 5 %

t =. 2 years

According to the question by using the formula we get,

⇒ S.I = \dfrac{15000 \times 5 \times 2}{100}

100

15000×5×2

⇒ S.I = \dfrac{150000}{100}

100

150000

⇒ S.I = \sf\dfrac{\cancel{150000}}{\cancel{100}}

100

150000

➠ S.I = Rs 1500

❸ Now, we have to find the difference between C.I and S.I we get,

⇒ Difference = 1537.5 - 1500

➥ Difference = Rs 37.5

\therefore∴ The difference between Compound Interest and SIMPLE Interest is Rs 37.5 .



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