Find the difference: [3(1/5)] – (7/10)

1.	Find the difference: [3(1/5)] – (7/10)
Answer» [3(1/5)] – (7/10) Convert mixed fraction into improper fraction, = [3(1/5)] = (16/5) = (16/5)-(7/10) For subtraction of two unlike fractions, first change them to the like fractions. LCM of 5, 10 = 10 Now, let us change each of the given fraction into an equivalent fraction having 10 as the denominator. = [(16/5) × (2/2)] = (32/10) = [(7/10) × (1/1)] = (7/10) Then, = (32/10) – (7/10) = (32-7)/10 = (25/10) … [÷ by 5] = (5/2) = [2(1/2)]

Answer»

[3(1/5)] – (7/10)

Convert mixed fraction into improper fraction,

= [3(1/5)] = (16/5)

= (16/5)-(7/10)

For subtraction of two unlike fractions, first change them to the like fractions.

LCM of 5, 10 = 10

Now, let us change each of the given fraction into an equivalent fraction having 10 as the denominator.

= [(16/5) × (2/2)] = (32/10)

= [(7/10) × (1/1)] = (7/10)

Then,

= (32/10) – (7/10)

= (32-7)/10

= (25/10) … [÷ by 5]

= (5/2)

= [2(1/2)]

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