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Find the deviation using median of the following observations: 15,19,20,28,16. |
Answer» Solution :TAKING in ascending ORDER ![]() Here `n=5` (odd) Median `M=(n+1)/2` th term `=(5+1)/2` th term `=` 3rd term `=19` Mean deviation `=(sum_(i=1)^(n)|x_(i)-M|)/n=17/5=3.4` |
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