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Find the derivative of xsinx by first principle? |
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Answer» x cosx xcosx Yes this question is there in miscellaneous example This question is there in miscellaneous solved example Hope this is helpful to u Proof:f(x)=xsinx f\'(x)=ddx[x]sinx+xddx[sinx] f\'(x)=1sinx+xcosx f\'(x)=xcosx+sinx |
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