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Find the derivative of tan(x)/x |
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Answer» Step-by-step EXPLANATION: They are as follows: (SINX)′=cosx,(cosx)′=−sinx. Using the quotient RULE it is easy to obtain an expression for the derivative of tangent: (tanx)′=(SINXCOSX)′=(sinx)′cosx−sinx(cosx)′cos2x=cosx⋅cosx−sinx⋅(−sinx)cos2x=cos2x+sin2xcos2 |
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