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| 1. |
find the derivative of sin2x |
| Answer» {tex}let\\,y = \\sin 2x{/tex}{tex}differentiating\\,with\\,respect\\,to\\,x{/tex}{tex}{{dy} \\over {dx}} = {d \\over {dx}}\\left( {\\sin 2x} \\right){/tex}{tex} = \\cos 2x{d \\over {dx}}\\left( {2x} \\right){/tex}{tex} = 2\\cos 2x{/tex} | |