1.

Find the derivative of Sin(1-4x²)I using chain rule

Answer»

\(\frac{d}{dx}\) sin(1 - 4x2) = cos(1 - 4x2\(\frac{d}{dx}\) (1 - 4x2)

= cos(1 - 4x2\((\frac{d}{dx}1-4\,\frac{d}{dx}x^2)\)

= cos(1 - 4x2) (0 - 8x)

= -8x cos(1 - 4x2)



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