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Find the derivative of Sin(1-4x²)I using chain rule |
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Answer» \(\frac{d}{dx}\) sin(1 - 4x2) = cos(1 - 4x2) \(\frac{d}{dx}\) (1 - 4x2) = cos(1 - 4x2) \((\frac{d}{dx}1-4\,\frac{d}{dx}x^2)\) = cos(1 - 4x2) (0 - 8x) = -8x cos(1 - 4x2) |
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