Find the depth at which the value of g becomes 25% of that at the surface of the earth. (Radius of the earth = 6400 km)

Find the depth at which the value of g becomes 25% of that at the surf

1.	Find the depth at which the value of g becomes 25% of that at the surface of the earth. (Radius of the earth = 6400 km)
Answer» SOLUTION :G at a depth `g_(d) = g(1-(d)/(R))` In this problem, `g_(d) = (25)/(100)g = 0.25 g` SUBSTITUTING `g_(d) = 0.25g` and R = 6400 km we GET d = 4800 km