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Find the density of the block of wood that floats in water with 0.1 of its volume above water. (a)0.9g/cc (b)0.3g/cc (c)0.1g/cc (d)0.2g/cc |
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Answer» The density of the block is 0.9g/cc.Explanation:The block has 0.1 of its part above WATER. Let volume be x.This means the part under water is 0.9x.THUS, the buoyant force applied by water on the block is: density of water * 0.9x * g.The weight on the block is: mg = density of block * x * gThus we know that if the block floats, then the net force is 0.This implies, Buoyant force - mg = 0Therefore, buoyant force = mgThus, density of water * 0.9x * g = density of block * x * gDensity of water = 1g/cm^3Thus, SOLVING this we get the answer as 0.9g/cc (cm^3)Thus, OPTION a is right.HOPE THIS HELPS YOU... |
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