Find the de Broglie's wavelength of the electron in the first Bohr's o

1.	Find the de Broglie's wavelength of the electron in the first Bohr's orbit ?
Answer» De Broglie wavelength $\gamma = \frac{h}{mv} \\ \\ where \\ \gamma = wavelength \: of \: radiation \\ h = planks \: constant \\ m = mass \: of \: electron \\ v = <klux>VELOCITY</klux> \: of \: electron \\$ A/c to BOHR's velocity of electron in first orbit $v = v_{o} \times \frac{z}{n} \\ \\ where \\ v = velocity \: of \: electron \: \\ v_{o} = 2.18 \times {10}^{6} m {s}^{ - 1} \\ z = atomic \: no. \\ n = no. \: of \: orbit$ Now LET here is the ATOM of Hydrogen then, d $v = v_{o} \times \frac{z}{n} \\ \\ v = 2.18 \times {10}^{6} \times \frac{1}{1} \\ \\ :. \: v = 2.18 \times {10}^{6}$ Now, In De Broglie wavelength $\gamma = \frac{h}{mv} \\ \\ \gamma = \frac{6.6 \times {10}^{ - 34} }{9.1 \times {10}^{ - 31} \times 2.18 \times {10}^{6} } \\ \\ \gamma = \frac{6.6 \times {10}^{ (- 34 + 31 - 6)} }{9.1 \times 2.18} \\ \\ \gamma = 0.3326948281 \times {10}^{ - 9} m$ ___________________________ ●•••••• ☆Brainly Star☆ •••••••●

Find the de Broglie's wavelength of the electron in the first Bohr's orbit ?